万年历
本帖最后由 komany 于 2010-12-8 12:16 编辑#include "stdio.h"
void main()
{
int leap_year(int y);
int count_leap(long year);
int monthdays(int month,long year);
void monthprint(long year,int month);
int month=0;
long int year=0;
char choose;
clrscr();
do
{printf ("\n\nPlease input one integer number as 'year'(0~3000):\n");
scanf ("%ld",&year);
if (year<0||year>3000) printf ("ERROR,please input again!");
}
while (year<0||year>3000);
printf ("\n\n");
do
{printf ("please input the month(1~12)\n\n");
scanf ("%d",&month);
if (month<=0||month>12) printf ("please input again!");
}
while (month<=0||month>12);
printf ("\n\n\n");
printf("\t\t\t\t%ld\t%d\n\n",year,month);
printf
("\n********************************************************************************\n");
printf("\t\t Sun\t Mon\t Tue\t Wen\t Thu\t Fri\t Sat\n");
monthprint(year,month);
printf("\n\n");
}
int leap_year(int y)
{ int i;
if (y%4==0&&y%100!=0||y%400==0) i=1;
else i=0;
return i;
}
//多谢N大的教导，下面/**/的里面是N大优化的代码
/*int leap_year(int y)
{
return (!(y%4)&&y%100 )|| !(y%400) ;
}
*/
int count_leap(long year)
{
int i=0,j,min,max;
if(year>2006) {min=2006;max=year;}
else {min=year+1;max=2006;}
for(j=min;j<max;j++)
if(leap_year(j)) i++;
return i;
}
int monthdays(int month,long year)
{
int sum=0,i,j;
if(year>=2006)
{ int t={31,0,31,30,31,30,31,31,30,31,30,31};
j=month-1;
if(leap_year(year)) t=29;
else t=28;
for(i=0;i<j;i++)
sum=sum+t;
}
else
{ int t1={31,30,31,30,31,31,30,31,30,31,0,31};
j=12-month;
if(leap_year(year)) t1=29;
else t1=28;
for(i=0;i<=j;i++)
sum=sum+t1;
}
return sum;
}
void monthprint(long year,int month)
{
int t={31,0,31,30,31,30,31,31,30,31,30,31};
int i,y,weekday=0;
long days=0;
if(leap_year(year)) t=29;
else t=28;
y=t;
if(year>2006)
{
days=(year-2006)*365+count_leap(year)+monthdays(month,year);
weekday=days%7;
}
else if(year<2006)
{days=(2005-year)*365+count_leap(year)+monthdays(month,year);
weekday=7-days%7;
}
else
{days=monthdays(month,year);weekday=days%7;}
for (i=1;i<=weekday+2;i++)
printf ("\t");
for (i=1;i<=y;i++)
{if ((i+weekday-1)%7==0) printf ("\n\n\t\t%3d\t",i);
else printf ("%3d\t",i);};
printf
("\n********************************************************************************\n\n");
}
不错 ~
int leap_year(int y)
{
return (!(y%4)&&y%100 )|| !(y%400) ;
}
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