来个CrackMe (level 4)
来个CrackMe (level 4) bug????????????name:9999999999
serial:1111111111
004010B7 .33FF xor edi,edi
004010B9 .BA 00000000 mov edx,0
004010BE .52 push edx
004010BF >0FB69F 1B304000 movzx ebx,byte ptr ds:
004010C6 .0FB68F 1A304000 movzx ecx,byte ptr ds:
004010CD .8BF1 mov esi,ecx
004010CF .6BC3 03 imul eax,ebx,3
004010D2 .03F0 add esi,eax
004010D4 .8BC3 mov eax,ebx
004010D6 .F7E3 mul ebx
004010D8 .03F0 add esi,eax
004010DA .8BC1 mov eax,ecx
004010DC .F7E1 mul ecx
004010DE .03F0 add esi,eax
004010E0 .0FAFD9 imul ebx,ecx
004010E3 .6BDB 02 imul ebx,ebx,2
004010E6 .03F3 add esi,ebx
004010E8 .8BC6 mov eax,esi
004010EA .BA 02000000 mov edx,2
004010EF .F6F2 div dl
004010F1 .6BC0 0E imul eax,eax,0E
004010F4 .0287 1C304000 add al,byte ptr ds:
004010FA .5A pop edx
004010FB .3A82 07304000 cmp al,byte ptr ds:
00401101 .75 46 jnz short crackme#.00401149
00401103 .83C7 03 add edi,3
00401106 .83FF 09 cmp edi,9
00401109 .74 04 je short crackme#.0040110F
算法如上,是从serial推注册名来验证的 是的~~~ 呵呵 有点意外
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